Wiki .5% Bupivacaine units

Lacybarfield

Contributor
Messages
10
Location
Cordele, GA
Best answers
0
if .33ml was injected of .5% bupivacaine how many units would be billed. Can someone verify if i calculated this right.
.5% BUPIVACAINE
J0665 BUPIVACAINE .5MG (HCPCS)
5MG/1ML (BOTTLE)


THIS IS HOW YOU CACULATE IF .33 ML WAS INJECTED

.33ML WAS INJECTED, SO YOU HAVE TO ROUND UP TO = 1ML

YOU HAVE TO CONVERT THE 1ML TO MGs, SO THE BOTTLE LETS YOU KNOW THAT 5MG= 1ML

SO THAT LETS YOU KNOW THAT 5MG WAS INJECTED

TAKE THE 5MG / .5MG (HCPCS CODE) = THIS IS HOW YOU GET THE UNITS

5MG DIVIDE .5MG = 10 UNITS

10 UNITS WAS INJECTED



THIS IS HOW YOU CACULATE IF 1ML WAS INJECTED

YOU HAVE TO CONVERT THE 1ML TO MGs, SO THE BOTTLE LETS YOU KNOW THAT 5MG=1ML

SO THAT LETS YOU KNOW THAT 5MG WAS INJECTED

TAKE THE 5MG / .5MG (HCPCS CODE) = THIS IS HOW YOU GET THE UNITS

5MG DIVIDE .5MG = 10 UNITS

10 UNITS WAS INJECTED
 
Unfortunately, you are not correct. And you're misunderstanding the bottle. "5 mg. = 1 ml" means that in each ml of fluid in the bottle there is 5 mg (weight) of bupivacaine.

The ml (volume) of the solution injected is not what you code from. You code only the weight of the medication. Millileters are a different measurement than milligrams, for (example fluid cups do not equal pounds because it depends on the liquid you're weighing), but you have enough information to code.

You know that for each ml of injectable fluid, there is within that 5 mg of bupivacaine.
The code J0665 is reportable with a base dosage of 0.5 mg. BUT....that's the weight within a full milliliter of this particular bottle of bupivacaine. A full milliliter wasn't injected into your patient however. Only .33 milliliters was injected. You have to do math.

So, if .33 of a ml was injected, which is the volume, 1/3 of 5 mg. is the weight of the medication that would be present within that volume of .33 milliliters.
.33 x 5= 1.65 mg is the dosage within a .33 ml injection. Round that up to 2 mg. because you can't report fractional units. If 1/2 a mg is the dosage, you would have four units of J0665. And if this is a single dose vial, you can report the wastage.

In your example, you would have reported 5 mg of bupivacaine, (0.5 x 10 units) = 5 mg, which is the weight of the medication in the entire milliliter. You would have reported 3 times what was actually given.
 
.33 x 5= 1.65 mg is the dosage within a .33 ml injection. Round that up to 2 mg. because you can't report fractional units. If 1/2 a mg is the dosage, you would have four units of J0665. And if this is a single dose vial, you can report the wastage.

0.5 mg x 4 (units) is 2 mg. medication (rounded up from 1.65).

If 1 ml of volume was injected, the bottle tells you that there is 5 mg. (weight) of the drug in that volume. that would be 10 units. (0.5. x 10 units is 5 mg).
 
Top